Python Program to find Armstrong Number

In this article we will learn Python program to check whether the given number is Armstrong or not. First let us understand what is Armstrong?. An Armstrong number is a number that is equal to the sum of the Nth power of its individual digits.

Let me take one example, 153 is a 3 digit Armstrong number then 1^3 +5^3+3^3=153

Now we will write the code to find Armstrong Number in Python Script:

print("Enter the number")

#get the number

number = int(input())

#store it in a temp

temp = int(number)

Sum = 0

#loop till the quotient is 0

while(temp != 0):

rem  = temp % 10 #find reminder

Sum  = Sum + (rem * rem * rem) #cube reminder and add it to the Sum

temp = temp / 10 #find quotient, if 0 then loop again

#if the entered number and the Sum value matches, it is an Armstrong number

if(number == Sum):

print ("Armstrong Number")

else:

print ("Not an Armstrong Number")

Output:

Enter the number: 153

Armstrong Number

Python program to check whether the given number is Armstrong or not using For loop:

Number = int(input("\n Enter the number: "))

 # Initializing Sum and Number of Digits

Sum = 0

number = 0

# Calculating Number of individual digits

Temp = Number

while Temp > 0:

           number = number + 1

           Temp = Temp // 10

# Finding Armstrong Number

Temp = Number

for n in range(1, Temp + 1):

           Reminder = Temp % 10

           Sum = Sum + (Reminder ** number)

           Temp //= 10

if Number == Sum:

           print("\n %d is Armstrong Number.\n" %Number)

else:

           print("\n %d is Not a Armstrong Number.\n" %Number)

Output:

Enter the Number: 370

370 is Armstrong Number

Python Program to find Armstrong Number using recursion:

In this program allows the user to enter any positive integer and then, we will find given number is Armstrong or not using recursion

# Initializing Number of Digits

Sum = 0

Times = 0

# Calculating Number of individual digits

def Count_Of_Digits(Number):

           global Times

           if(Number > 0):

                      Times = Times + 1

                      Count_Of_Digits(Number // 10)

           return Times

#End of Count Of Digits Function

# Finding Armstrong Number

def Armstrong_Number(Number, Times):

           global Sum

           if(Number > 0):

                      Reminder = Number % 10

                      Sum = Sum + (Reminder ** Times)

                      Armstrong_Number(Number //10, Times)

           return Sum

#End of Armstrong Function

#User Input

Number = int(input("\n Enter the Number: "))

Times = Count_Of_Digits(Number)

Sum = Armstrong_Number(Number, Times)

if (Number == Sum):

    print("\n %d is Armstrong Number.\n" %Number)

else:

    print("\n %d is Not a Armstrong Number.\n" %Number) 

Output:

Enter the Number: 370

370 is Armstrong Number